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0.06x^2+0.6x+180=15x
We move all terms to the left:
0.06x^2+0.6x+180-(15x)=0
We add all the numbers together, and all the variables
0.06x^2-14.4x+180=0
a = 0.06; b = -14.4; c = +180;
Δ = b2-4ac
Δ = -14.42-4·0.06·180
Δ = 164.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14.4)-\sqrt{164.16}}{2*0.06}=\frac{14.4-\sqrt{164.16}}{0.12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14.4)+\sqrt{164.16}}{2*0.06}=\frac{14.4+\sqrt{164.16}}{0.12} $
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